1816 United States presidential election in Delaware

The 1816 United States presidential election in Delaware took place between 1 November and 4 December 1816, as part of the 1816 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.

1816 United States presidential election in Delaware

← 1812 1 November – 4 December 1816 1820 →
 
Nominee Rufus King James Monroe
Party Federalist Democratic-Republican
Home state New York Virginia
Running mate John E. Howard Daniel D. Tompkins
Electoral vote 3 0

Delaware cast three electoral votes for the Federalist candidate Rufus King over the Democratic-Republican candidate James Monroe. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. However one of the four electors did not end up casting their vote. The three electoral votes for Vice president were also not cast for King's running mate John E. Howard, but for Federalist Robert Goodloe Harper from Maryland.[1]

Results

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1816 United States presidential election in Delaware[2]
Party Candidate Votes Percentage Electoral votes
Federalist Rufus King 3
Democratic-Republican James Monroe 0
None Not Cast 1
Totals 4

See also

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References

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  1. ^ "1816 Presidential General Election Results". U.S. Election Atlas. Retrieved July 8, 2023.
  2. ^ "1816 Presidential Election". 270towin.com. Retrieved July 8, 2023.