1808 United States presidential election in Delaware

The 1808 United States presidential election in Delaware took place between 4 November and 7 December 1808, as part of the 1808 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

1808 United States presidential election in Delaware

← 1804 4 November – 7 December 1808 1812 →
 
Nominee Charles C. Pinckney James Madison
Party Federalist Democratic-Republican
Home state South Carolina Virginia
Running mate Rufus King George Clinton
Electoral vote 3 0

Delaware cast three electoral votes for the Federalist candidate Charles C. Pinckney over the Democratic-Republican candidate James Madison. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for Vice president were cast for Pinckney's running mate Rufus King from New York.[1]

Results

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1808 United States presidential election in Delaware[2]
Party Candidate Votes Percentage Electoral votes
Federalist Charles C. Pinckney 3
Democratic-Republican James Madison 0
Totals 3

See also

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References

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  1. ^ "1808 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
  2. ^ "1808 Presidential Election". 270towin.com. Retrieved July 9, 2023.