The 1796 United States presidential election in Delaware took place between 4 November and 7 December 1796, as part of the 1796 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for president and vice president.
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Delaware cast three electoral votes for the Federalist candidate and incumbent vice president John Adams over the Democratic-Republican candidate Thomas Jefferson. These electors were elected by the Delaware General Assembly, the state legislature, rather than by popular vote. The three electoral votes for vice president were cast for Adams' running mate Thomas Pinckney from South Carolina.[1]
Results
edit| 1796 United States presidential election in Delaware[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Federalist | John Adams | – | 100.00% | 3 | |
| Democratic-Republican | Thomas Jefferson | – | 0.00% | 0 | |
| Totals | – | – | 3 | ||
See also
editReferences
edit- ^ "1796 Presidential General Election Results". U.S. Election Atlas. Retrieved July 9, 2023.
- ^ "1796 Presidential Election". 270towin.com. Retrieved July 9, 2023.