Open main menu

1884 United States presidential election in Massachusetts

  (Redirected from United States presidential election in Massachusetts, 1884)

The 1884 United States presidential election in Massachusetts took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose 14 representatives, or electors to the Electoral College, who voted for president and vice president.

United States presidential election in Massachusetts, 1884

← 1880 November 4, 1884 1888 →
Turnout69.3%[1] Decrease 1.9 pp
  JamesGBlaine.png StephenGroverCleveland.png Bfbutler.jpg
Nominee James G. Blaine Grover Cleveland Benjamin Franklin Butler
Party Republican Democratic Greenback
Home state Maine New York Massachusetts
Running mate John A. Logan Thomas A. Hendricks Absolom Madden West
Electoral vote 14 0 0
Popular vote 146,724 122,352 24,382
Percentage 48.36% 40.33% 8.04%

President before election

Chester A. Arthur
Republican

Elected President

Grover Cleveland
Democratic

Massachusetts voted for the Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a narrow margin of 8.03%.

ResultsEdit

United States presidential election in Massachusetts, 1884[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican James Gillespie Blaine of Maine John Alexander Logan of Illinois 146,724 48.36% 14 100.00%
Democratic Grover Cleveland of New York Thomas Andrews Hendricks of Indiana 122,352 40.33% 0 0.00%
Greenback Benjamin Franklin Butler of Massachusetts Absolom Madden West of Mississippi 24,382 8.04% 0 0.00%
Prohibition John Pierce St. John of Kansas William Daniel of Maryland 9,923 3.26% 0 0.00%
N/A Others Others 2 0.01% 0 0.00%
Total 303,383 100.00% 14 100.00%

ReferencesEdit

  1. ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
  2. ^ "1884 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.