1836 United States presidential election in Delaware

The 1836 United States presidential election in Delaware took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

1836 United States presidential election in Delaware

← 1832 November 3 – December 7, 1836 1840 →
 
Nominee William Henry Harrison Martin Van Buren
Party Whig Democratic
Home state Ohio New York
Running mate Francis Granger Richard Johnson
Electoral vote 3 0
Popular vote 4,736 4,154
Percentage 53.24% 46.70%

County Results

President before election

Andrew Jackson
Democratic

Elected President

William Henry Harrison
Whig

Delaware voted for Whig candidate William Henry Harrison over the Democratic candidate, Martin Van Buren. Harrison won Delaware by a margin of 6.54%.

Results

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1836 United States presidential election in Delaware[1]
Party Candidate Votes Percentage Electoral votes
Whig William Henry Harrison 4,736 53.24% 3
Democratic Martin Van Buren 4,154 46.70% 0
N/A Other 5 0.06% 0
Totals 8,895 100.00% 3

Results by county

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1836 United States presidential election in Delaware[2]
County William Henry Harrison

Whig

Martin Van Buren

Democratic

Various candidates

Other parties

Margin Total votes cast
# % # % # % # %
Kent 1,205 53.70% 1,039 46.30% 0 0.00% 166 7.40% 2,244
New Castle 1,673 47.91% 1,814 51.95% 5 0.14% -141 -4.04% 3,492
Sussex 1,858 58.82% 1,301 41.18% 0 0.00% 557 17.63% 3,159
Total: 4,736 53.24% 4,154 46.70% 5 0.06% 582 6.54% 8,895

See also

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References

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  1. ^ "1836 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved August 4, 2012.
  2. ^ Burnham, Walter Dean (1955). Presidential ballots, 1836-1892. Internet Archive. Baltimore, Johns Hopkins Press. p. 320.