Peire de Montagut

  (Redirected from Pedro de Montaigu)

Peire de Montagut [1] (? – 28 January 1232) was Grand Master of the Knights Templar from 1218 to 1232. He took part in the Fifth Crusade and was against the Sultan of Egypt's conditions for raising the siege of Damietta. He was previously Master of the Crown of Aragon.

Peire de Montagut
Armoiries Pierre de Montaigu.svg
Coat of arms of Pere de Montagut
Grand Master of the Knights Templar
In office
Personal details
Died28 January 1232

Personal detailsEdit

A close friend of Guillaume de Chartres, it was most likely the trust the previous Grand Master had in him which meant he himself was elected so quickly in 1218. At the same time, the Grand Master of the Knights Hospitaller was Guérin de Montaigu, who is likely to have been Pere's brother. The close relationship between the two military orders during this period was probably a result of this.

Military recordEdit

His actions against the Muslim forces working for the capture of Jerusalem were so effective, that they were forced to propose a surrender. In return for the Templars calling off their siege at Damietta, the Islamic forces would return many Frankish soldiers, halt attacks on Jerusalem and most importantly, return the part of the True Cross, captured from the Europeans at the Battle of Hattin. Catholic pressure meant the Muslim terms were refused and the carnage continued. His military victories, aided by the Hospitaller knights, made him a renowned warrior.

He died in 1232 of apoplexy.[citation needed]


  1. ^ Known in Catalan as Pere de Montagut and in French as Pierre de Montaigu.
Religious titles
Preceded by
Guillaume de Chartres
Grand Master of the Knights Templar
Succeeded by
Armand de Périgord