2020 Cleveland Open – Doubles

Romain Arneodo and Andrei Vasilevski were the defending champions[1] but chose not to defend their title.

Doubles
2020 Cleveland Open
Final
ChampionsPhilippines Treat Huey
United States Nathaniel Lammons
Runners-upAustralia Luke Saville
Australia John-Patrick Smith
Score7–5, 6–2
Events
Singles Doubles
← 2019 · Cleveland Open · 2021 →

Treat Huey and Nathaniel Lammons won the title after defeating Luke Saville and John-Patrick Smith 7–5, 6–2 in the final.

Seeds edit

Draw edit

Key edit

First round Quarterfinals Semifinals Final
1   L Saville
  J-P Smith
77 6
WC   C Harrison
  R Harrison
64 3 1   L Saville
  J-P Smith
6 6
  S Ofner
  R Quiroz
4 2   J Cerretani
  M Cressy
4 4
  J Cerretani
  M Cressy
6 6 1   L Saville
  J-P Smith
66 6 [10]
3   LD Martínez
  MÁ Reyes-Varela
68 5   L Glasspool
  A Lawson
78 4 [6]
  R Cid Subervi
  S Mansouri
710 7   R Cid Subervi
  S Mansouri
3 68
  L Glasspool
  A Lawson
6 6   L Glasspool
  A Lawson
6 710
  R Gonzales
  R Roelofse
3 4 1   L Saville
  J-P Smith
5 2
  D Popko
  A Tabilo
4 5   T Huey
  N Lammons
7 6
  T Huey
  N Lammons
6 7   T Huey
  N Lammons
710 6
WC   Ian Dempster
  K Lovett
6 4 [10] WC   I Dempster
  K Lovett
68 4
4   D Novikov
  G Oliveira
4 6 [8]   T Huey
  N Lammons
6 77
  N Pasha
  Ma Redlicki
2 1   R Galloway
  H Hach Verdugo
3 65
  R Galloway
  H Hach Verdugo
6 6   R Galloway
  H Hach Verdugo
6 710
WC   James Hopper
  Nico Mostardi
4 4 2   J-s Nam
  M-k Song
3 68
2   J-s Nam
  M-k Song
6 6

References edit

  1. ^ "Cleveland Open is returning to Cleveland Racquet Club in February". Crain's Cleveland Business. September 20, 2019.

External links edit