Wotnarg

${\frac {dh}{dt}}=-{\frac {{\sqrt {(}}h)}{5}}$
${\frac {-5}{dt}}={\frac {\sqrt {h}}{dh}}$
$\int {\frac {dt}{-5}}=\int {\frac {dh}{\sqrt {h}}}$
$-1/5*t+C=2{\sqrt {h}}$
${\frac {-1/5*t+C}{2}}={\sqrt {h}}$
${\frac {(-1/5*t+C)^{2}}{4}}=h$
# Note: in the next step I kill the squared by sqrting both sides
$-1/5*(0)+C/4=17$
$C=17$

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