2019 St. Petersburg Open – Doubles

Matteo Berrettini and Fabio Fognini were the defending champions,[1] but Fognini chose not to participate this year. Berrettini played alongside Simone Bolelli, but lost in the final to Divij Sharan and Igor Zelenay, 3–6, 6–3, [8–10].

Doubles
2019 St. Petersburg Open
Final
ChampionsIndia Divij Sharan
Slovakia Igor Zelenay
Runners-upItaly Matteo Berrettini
Italy Simone Bolelli
Score6–3, 3–6, [10–8]
Events
Singles Doubles
← 2018 · St. Petersburg Open · 2020 →

Seeds edit

Draw edit

Key edit

Draw edit

First round Quarterfinals Semifinals Final
1   N Mektić
  F Škugor
6 6
PR   R Berankis
  J Tipsarević
3 4 1   N Mektić
  F Škugor
6 6
  N Monroe
  A Vasilevski
6 6   N Monroe
  A Vasilevski
4 2
WC   E Donskoy
  K Kravchuk
3 2 1   N Mektić
  F Škugor
5 1
4   M Demoliner
  M Middelkoop
6 2 [5]   D Sharan
  I Zelenay
7 6
  D Sharan
  I Zelenay
3 6 [10]   D Sharan
  I Zelenay
7 5 [10]
WC   E Karlovskiy
  A Rublev
77 2 [2]   R Carballés Baena
  A Molteni
5 7 [5]
  R Carballés Baena
  A Molteni
65 6 [10]   D Sharan
  I Zelenay
6 3 [10]
  F Nielsen
  T Pütz
6 6   M Berrettini
  S Bolelli
3 6 [8]
  M Fucsovics
  S Travaglia
4 4   F Nielsen
  T Pütz
4 6 [7]
  M Berrettini
  S Bolelli
6 6   M Berrettini
  S Bolelli
6 4 [10]
3   R Jebavý
  P Oswald
2 2   M Berrettini
  S Bolelli
7 7
  A Bublik
  M Kukushkin
64 3 2   S Gillé
  J Vliegen
5 5
  A Mannarino
  H Nys
77 6   A Mannarino
  H Nys
4 4
PR   J Kovalík
  H Podlipnik Castillo
4 4 2   S Gillé
  J Vliegen
6 6
2   S Gillé
  J Vliegen
6 6

References edit

  1. ^ "Dream Debut: Berrettini/Fognini Triumph In St. Petersburg". ATP Tour. 23 September 2018.

External links edit