2019 Kiskút Open – Doubles

This was the first edition of the tournament.[1]

Doubles
2019 Kiskút Open
Final
ChampionsRomania Irina Bara
Belgium Maryna Zanevska
Runners-upUzbekistan Akgul Amanmuradova
Romania Elena Bogdan
Score3–6, 6–2, [10–8]
Events
Singles Doubles
Kiskút Open · 2020 →

Irina Bara and Maryna Zanevska won the title, defeating Akgul Amanmuradova and Elena Bogdan in the final, 3–6, 6–2, [10–8].

Seeds edit

Draw edit

Key edit

Draw edit

First round Quarterfinals Semifinals Final
1   G García Pérez
  F Stollár
3 0r
    I Bara
  M Zanevska
6 1   I Bara
  M Zanevska
6 6
    RL Jani
  P Ormaechea
5 6 [10]   RL Jani
  P Ormaechea
2 3
    M Chwalińska
  A Nagy
7 3 [7]   I Bara
  M Zanevska
77 6
3   N Dascălu
  D Kovinić
w/o 3   N Dascălu
  D Kovinić
63 1
    V Juhászová
  M Klaffner
3   N Dascălu
  D Kovinić
6 6
    A Bondár
  R Šramková
0 6 [10]   A Bondár
  R Šramková
4 2
    G Cé
  S Waltert
6 4 [8]   I Bara
  M Zanevska
3 6 [10]
    M Chernyshova
  C Škamlová
w/o 4   A Amanmuradova
  E Bogdan
6 2 [8]
WC   Á Bukta
  T Pereira
  M Chernyshova
  C Škamlová
2 64
WC   B Békefi
  D Drahota-Szabó
3 4 4   A Amanmuradova
  E Bogdan
6 77
4   A Amanmuradova
  E Bogdan
6 6 4   A Amanmuradova
  E Bogdan
2 6 [10]
    M Bulgaru
  IG Ghioroaie
6 6 2   A Anshba
  A Dețiuc
6 4 [4]
    J Marková
  D Seguel
4 2   M Bulgaru
  IG Ghioroaie
2 3
    N Potočnik
  N Radišič
4 3 2   A Anshba
  A Dețiuc
6 6
2   A Anshba
  A Dețiuc
6 6

References edit

  1. ^ "W60 Székesfehérvár". www.itftennis.com.