2018 Milex Open – Doubles

Doubles
Doubles
2018 Milex Open
Final
Champions	Leander Paes; Miguel Ángel Reyes-Varela;
Runners-up	Ariel Behar; Roberto Quiroz;
Score	4–6, 6–3, [10–5]
Events
Singles	Doubles

Juan Ignacio Londero and Luis David Martínez were the defending champions but only Londero chose to defend his title, partnering Tomás Lipovšek Puches. Londero lost in the semifinals to Leander Paes and Miguel Ángel Reyes-Varela.

Paes and Reyes-Varela won the title after defeating Ariel Behar and Roberto Quiroz 4–6, 6–3, [10–5] in the final.

Seeds edit

First round					Quarterfinals					Semifinals					Final

1	P Cuevas D Marrero	6	6
	G Andreozzi G Durán	3	3		1	P Cuevas D Marrero	3	7	[7]
WC	R Cid Subervi J Hernández-Fernández	0	3		WC	H Dellien V Estrella Burgos	6	5	[10]
WC	H Dellien V Estrella Burgos	6	6							WC	H Dellien V Estrella Burgos	3	6	[3]
3	M Arévalo J Nedunchezhiyan	6	7⁷								A Behar R Quiroz	6	3	[10]
WC	J Olivares C Rodríguez	3	6²		3	M Arévalo J Nedunchezhiyan	7	4	[7]
	R Dutra Silva P Lorenzi	2	6	[5]		A Behar R Quiroz	5	6	[10]
	A Behar R Quiroz	6	4	[10]												A Behar R Quiroz	6	3	[5]
	T Lipovšek Puches JI Londero	w/o													2	L Paes MÁ Reyes-Varela	4	6	[10]
	F Bagnis C Berlocq					T Lipovšek Puches JI Londero	6⁵	7⁸	[11]
	S Galdós T Monteiro	6⁴	6²		4	G Escobar F Romboli	7⁷	6⁶	[9]
4	G Escobar F Romboli	7⁷	7⁷								T Lipovšek Puches JI Londero	4	6³
	G Melzer J Melzer	6	6							2	L Paes MÁ Reyes-Varela	6	7⁷
	A Begemann F Polášek	3	3			G Melzer J Melzer	5	6⁷
	G Elias P Krstin	3	0		2	L Paes MÁ Reyes-Varela	7	7⁹
2	L Paes MÁ Reyes-Varela	6	6