2016 Open Harmonie mutuelle – Doubles

Grégoire Burquier and Alexandre Sidorenko were the defending champions, but only Sidorenko chose to defend his title partnering Axel Michon. Sidorenko lost to Ivan and Matej Sabanov in the first round.

Doubles
2016 Open Harmonie mutuelle
Final
ChampionsAustralia Rameez Junaid
Sweden Andreas Siljeström
Runners-upUnited States James Cerretani
Netherlands Antal van der Duim
Score5–7, 7–6(7–4), [10–8]
Events
Singles Doubles
← 2015 · Open Harmonie mutuelle · 2017 →

Rameez Junaid and Andreas Siljeström won the title after defeating James Cerretani and Antal van der Duim 5–7, 7–6(7–4), [10–8] in the final.

Seeds edit

Draw edit

Key edit

First round Quarterfinals Semifinals Final
1   R Junaid
  A Siljeström
6 64 [10]
WC   M Gicquel
  D Guez
1 77 [7] 1   R Junaid
  A Siljeström
6 65 [10]
  A Michon
  A Sidorenko
3 2   I Sabanov
  M Sabanov
4 77 [6]
  I Sabanov
  M Sabanov
6 6 1   R Junaid
  A Siljeström
6 1 [10]
4   M Kowalczyk
  A Majchrowicz
6 6 WC   M Authom
  J Eysseric
4 6 [8]
  A Karatsev
  C Lestienne
3 3 4   M Kowalczyk
  A Majchrowicz
5 5
WC   M Authom
  J Eysseric
5 6 [10] WC   M Authom
  J Eysseric
7 7
WC   H Nys
  M Teixeira
7 3 [5] 1   R Junaid
  A Siljeström
5 77 [10]
  S Arends
  G Oliveira
6 4 [3]   J Cerretani
  A van der Duim
7 64 [8]
  T Kamke
  T-S Weissborn
4 6 [10]   T Kamke
  T-S Weissborn
62 6 [10]
Alt   L Giustino
  R Ramanathan
5 2 3   M Bhupathi
  J Marray
77 2 [5]
3   M Bhupathi
  J Marray
6 6   T Kamke
  T-S Weissborn
5 3
  G Barrère
  Q Halys
4 4   J Cerretani
  A van der Duim
7 6
  Y Mertens
  I Sijsling
6 6   Y Mertens
  I Sijsling
4 3
  J Cerretani
  A van der Duim
6 6   J Cerretani
  A van der Duim
6 6
2   F Moser
  A Satschko
4 4

References edit