Nadia Petrova and Meghann Shaughnessy defeated Cara Black and Rennae Stubbs in the final, 7–5, 6–2 to win the doubles tennis title at the 2004 WTA Tour Championships.[1]
| Doubles | |
|---|---|
| 2004 WTA Tour Championships | |
| Champions |  Nadia Petrova Meghann Shaughnessy |
| Runners-up |  Cara Black Rennae Stubbs |
| Score | 7–5, 6–2 |
Virginia Ruano Pascual and Paola Suárez were the defending champions, but were defeated in the semifinals by Black and Stubbs.
Seeds edit
Virginia Ruano Pascual / 
Paola Suárez (semifinals)
Svetlana Kuznetsova / Elena Likhovtseva (semifinals)
Draw edit
Key edit
- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Finals edit
| Semifinals | Final | ||||||||||||
| 1 |  Virginia Ruano Pascual Paola Suárez
| 69 | 4 | ||||||||||
| Cara Black Rennae Stubbs
| 711 | 6 | |||||||||||
| Cara Black Rennae Stubbs
| 5 | 2 | |||||||||||
| Nadia Petrova Meghann Shaughnessy
| 7 | 6 | |||||||||||
| Nadia Petrova Meghann Shaughnessy
| 6 | 6 | |||||||||||
| 2 | Svetlana Kuznetsova Elena Likhovtseva
| 3 | 2 | ||||||||||
References edit
- ^ "2004 WTA Tour Championships presented by Porsche" (PDF). WTA Tennis. Retrieved 2020-05-21.