1998 Florida Attorney General election

The 1998 Florida Attorney General election was held on November 3, 1998. Democratic incumbent Bob Butterworth defeated Republican nominee David H. Bludworth with 59.56% of the vote. As of 2024, this was the last time a Democrat was elected Florida Attorney General.

1998 Florida Attorney General election

← 1994 November 3, 1998 2002 →
 
Nominee Bob Butterworth David H. Bludworth
Party Democratic Republican
Popular vote 2,301,328 1,562,269
Percentage 59.6% 40.4%

Butterworth:      50–60%      60–70%      70–80%      80–90%      >90%
Bludworth:      50–60%      60–70%      70–80%      80–90%      >90%
Tie:      40–50%      50%
     No votes

Attorney General before election

Bob Butterworth
Democratic

Elected Attorney General

Bob Butterworth
Democratic

Primary elections edit

Primary elections were held on September 1, 1998.[1]

Democratic primary edit

Candidates edit

Results edit

Democratic primary results[1]
Party Candidate Votes %
Democratic Bob Butterworth 475,757 81.80
Democratic Ellis Rubin 105,865 18.20
Total votes 581,622 100.00

Republican primary edit

Candidates edit

Results edit

Republican primary results[1]
Party Candidate Votes %
Republican David H. Bludworth 298,375 53.89
Republican Fred Dudley 255,274 46.11
Total votes 553,649 100.00

General election edit

Candidates edit

  • Bob Butterworth, Democratic
  • David H. Bludworth, Republican

Results edit

1998 Florida Attorney General election[2]
Party Candidate Votes % ±%
Democratic Bob Butterworth 2,301,328 59.56%
Republican David H. Bludworth 1,562,269 40.44%
Majority 739,059
Turnout
Democratic hold Swing

References edit

  1. ^ a b c "September 1, 1998 Primary Election". Secretary of State of Florida. 1998. Retrieved June 1, 2021.
  2. ^ "November 3, 1998 General Election". Secretary of State of Florida. 1998. Retrieved June 1, 2021.