1998 Budapest Lotto Open – Doubles

Amanda Coetzer and Alexandra Fusai were the defending champions but did not compete that year.

Doubles
1998 Budapest Lotto Open
Final
ChampionsSpain Virginia Ruano Pascual
Argentina Paola Suárez
Runners-upRomania Cătălina Cristea
Argentina Laura Montalvo
Score4–6, 6–1, 6–1
Events
Singles Doubles
← 1997 · Budapest Lotto Open · 1999 →

Virginia Ruano Pascual and Paola Suárez won in the final 4–6, 6–1, 6–1 against Cătălina Cristea and Laura Montalvo.

Seeds edit

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated.

  1.   Virginia Ruano Pascual /   Paola Suárez (champions)
  2.   Cătălina Cristea /   Laura Montalvo (final)
  3.   Svetlana Krivencheva /   Eva Melicharová (quarterfinals)
  4.   Laura Golarsa /   Liezel Horn (semifinals)

Draw edit

Key edit

First round Quarterfinals Semifinals Final
1   V Ruano Pascual
  P Suárez
6 6  
    E Bes
  K Marosi
0 1   1   V Ruano Pascual
  P Suárez
6 6  
    S Naćuk
  P Wartusch
6 1 6     S Naćuk
  P Wartusch
1 0  
    J Halard-Decugis
  J Husárová
3 6 4 1   V Ruano Pascual
  P Suárez
6 6  
4   L Golarsa
  L Horn
6 4 6 4   L Golarsa
  L Horn
3 3  
    P Gáspár
  A-G Sidot
4 6 3 4   L Golarsa
  L Horn
6 6  
WC   Z Gubacsi
  R Kuti-Kis
6 6   WC   Z Gubacsi
  R Kuti-Kis
4 2  
Q   E Doman
  A Piski
4 3   1   Virginia Ruano Pascual
  Paola Suárez
4 6 6
    A Dechaume-Balleret
  B Rittner
      2   Cătălina Cristea
  Laura Montalvo
6 1 1
    N Dechy
  L Ghirardi
w/o         N Dechy
  L Ghirardi
6 6  
    E Kulikovskaya
  K Studeníková
2 1   3   S Krivencheva
  E Melicharová
4 2  
3   S Krivencheva
  E Melicharová
6 6       N Dechy
  L Ghirardi
2 6 1
    S Cecchini
  W Probst
4 1   2   C Cristea
  L Montalvo
6 2 6
    S Farina
  S Testud
6 6       S Farina
  S Testud
3 3  
    V Csurgó
  T Križan
3 5   2   C Cristea
  L Montalvo
6 6  
2   C Cristea
  L Montalvo
6 7  

External links edit