Group B of the 1978 FIFA World Cup was one of two groups of nations competing for the de facto semi-finals of the 1978 FIFA World Cup. The group's first round of matches began on 14 June and its last matches were played on 21 June. All six group matches were played either at the Estadio Ciudad de Mendoza in Mendoza, or the Estadio Gigante de Arroyito in Rosario. The group consisted of Argentina, Brazil, Peru and Poland. Argentina advanced to the final match, and Brazil advanced to the third place match.[1]
Qualified teams edit
The winners of Group 2 and 4 and the runners-up of Group 1 and 3 qualified for Group B of the second round.
Group | Winners |
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2 | Poland |
4 | Peru |
Group | Runners-up |
1 | Argentina |
3 | Brazil |
Standings edit
Pos | Team | Pld | W | D | L | GF | GA | GD | Pts | Qualification |
---|---|---|---|---|---|---|---|---|---|---|
1 | Argentina | 3 | 2 | 1 | 0 | 8 | 0 | +8 | 5 | Advance to final |
2 | Brazil | 3 | 2 | 1 | 0 | 6 | 1 | +5 | 5 | Advance to third place play-off |
3 | Poland | 3 | 1 | 0 | 2 | 2 | 5 | −3 | 2 | |
4 | Peru | 3 | 0 | 0 | 3 | 0 | 10 | −10 | 0 |
Source: FIFA
Matches edit
Brazil vs Peru edit
Brazil
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Peru
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Argentina vs Poland edit
Argentina
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Poland
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Peru vs Poland edit
Peru
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Poland
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Argentina vs Brazil edit
Argentina
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Brazil
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Brazil vs Poland edit
Brazil
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Poland
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Argentina vs Peru edit
Argentina
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Peru
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See also edit
References edit
- ^ "1978 World Cup". fifa.com. Archived from the original on 30 March 2015. Retrieved 3 April 2018.