The 1918 Rhode Island gubernatorial election was held on November 5, 1918. Incumbent Republican Robert Livingston Beeckman defeated Democratic nominee Alberic A. Archambault with 53.11% of the vote.
 | |||||||||||||||||
| |||||||||||||||||
| |||||||||||||||||
| |||||||||||||||||
General election edit
Candidates edit
Major party candidates
- Robert Livingston Beeckman, Republican
- Alberic A. Archambault, Democratic
Other candidates
- Ernest Sherwood, Socialist
Results edit
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Robert Livingston Beeckman (incumbent) | 42,682 | 53.11% | ||
| Democratic | Alberic A. Archambault | 36,031 | 44.84% | ||
| Socialist | Ernest Sherwood | 1,648 | 2.05% | ||
| Majority | 6,651 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References edit
- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved May 20, 2020.