2019 Hungarian Open – Doubles

Dominic Inglot and Franko Škugor were the defending champions,[1] but Škugor chose to compete in Barcelona instead. Inglot played alongside Rohan Bopanna, but lost in the quarterfinals to Andre Begemann and Ernests Gulbis.

Doubles
2019 Hungarian Open
Final
ChampionsUnited Kingdom Ken Skupski
United Kingdom Neal Skupski
Runners-upNew Zealand Marcus Daniell
Netherlands Wesley Koolhof
Score6–3, 6–4
Details
Draw16 (2 WC )
Seeds4
Events
Singles Doubles
← 2018 · Hungarian Open (tennis) · 2020 →

Ken and Neal Skupski won the title, defeating Marcus Daniell and Wesley Koolhof in the final, 6–3, 6–4.

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   R Bopanna
  D Inglot
6 7
Alt   T Fabbiano
  J Millman
3 5 1   R Bopanna
  D Inglot
3 4
Alt   A Begemann
  E Gulbis
6 7 Alt   A Begemann
  E Gulbis
6 6
  R Jebavý
  A Molteni
4 5 Alt   A Begemann
  E Gulbis
2 77 [6]
3   K Skupski
  N Skupski
6 77 3   K Skupski
  N Skupski
6 62 [10]
WC   M Valkusz
  N Zimonjić
0 64 3   K Skupski
  N Skupski
78 5 [10]
  R Lindstedt
  A-u-H Qureshi
3 6 [9]   M Demoliner
  D Sharan
66 7 [7]
  M Demoliner
  D Sharan
6 4 [11] 3   K Skupski
  N Skupski
6 6
  M Daniell
  W Koolhof
6 6   M Daniell
  W Koolhof
3 4
  H Hurkacz
  F Martin
2 3   M Daniell
  W Koolhof
6 77
WC   G Borsos
  P Nagy
6 3 [8] 4   R Haase
  F Nielsen
4 65
4   R Haase
  F Nielsen
2 6 [10]   M Daniell
  W Koolhof
3 6 [10]
  R Albot
  N Basilashvili
3 3   K Krawietz
  A Mies
6 2 [8]
  K Krawietz
  A Mies
6 6   K Krawietz
  A Mies
3 6 [10]
  L Bambridge
  J O'Mara
3 6 [10]   L Bambridge
  J O'Mara
6 4 [6]
2   S González
  M Middelkoop
6 3 [8]

References

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  1. ^ "Inglot/Skugor Earn Maiden Team Title In Budapest". ATP Tour. 29 April 2018. Retrieved 20 April 2019.
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