1999 ATP Tour World Championships – Doubles

Sébastien Lareau and Alex O'Brien defeated Mahesh Bhupathi and Leander Paes in the final, 6–3, 6–2, 6–2 to win the doubles tennis title at the 1999 ATP Tour World Championships.[1]

Doubles
1999 ATP Tour World Championships
Final
ChampionsCanada Sébastien Lareau
United States Alex O'Brien
Runners-upIndia Mahesh Bhupathi
India Leander Paes
Score6–3, 6–2, 6–2
Details
Draw8
Events
Singles Doubles
← 1998 · ATP Tour World Championships · 2000 →

Jacco Eltingh and Paul Haarhuis were the reigning champions, but did not compete together in 1999. Eltingh retired from the sport on November 22, 1998; Haarhuis qualified with Jared Palmer, but was eliminated in the round-robin stage.

Seeds

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  1.   Mahesh Bhupathi /   Leander Paes (final)
  2.   Todd Woodbridge /   Mark Woodforde (semifinals)
  3.   Ellis Ferreira /   Rick Leach (round robin)
  4.   Sébastien Lareau /   Alex O'Brien (champions)
  5.   David Adams /   John-Laffnie de Jager (round robin, withdrew due to a flu of de Jager)
  6.   Wayne Black /   Sandon Stolle (semifinals)
  7.   Paul Haarhuis /   Jared Palmer (round robin)
  8.   Piet Norval /   Kevin Ullyett (round robin)
  9.   Jiří Novák /   David Rikl (round robin)

Draw

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Finals

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Semifinals Final
            
1   Mahesh Bhupathi
  Leander Paes
5 6 7
2   Todd Woodbridge
  Mark Woodforde
7 2 5
1   Mahesh Bhupathi
  Leander Paes
3 2 2    
4   Sébastien Lareau
  Alex O'Brien
6 6 6    
4   Sébastien Lareau
  Alex O'Brien
6 7  
6   Wayne Black
  Sandon Stolle
3 5  

Gold group

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    Bhupathi
  Paes
  Ferreira
  Leach
  Black
  Stolle
  Norval
  Ullyett
RR
W–L
Set
W–L
Game
W–L
Standings
1   Mahesh Bhupathi
  Leander Paes
6–4, 6–4 7–6(7–5), 5–7, 2–6 7–6(7–1), 6–3 2–1 5–2 39–36 2
3   Ellis Ferreira
  Rick Leach
4–6, 4–6 6–3, 6–2 3–6, 3–6 1–2 2–4 26–29 4
6   Wayne Black
  Sandon Stolle
6–7(5–7), 7–5, 6–2 3–6, 2–6 7–6(7–5), 6–1 2–1 4–3 37–33 1
8   Piet Norval
  Kevin Ullyett
6–7(1–7), 3–6 6–3, 6–3 6–7(5–7), 1–6 1–2 2–4 28–32 3

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

Green group

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    Woodbridge
  Woodforde
  Lareau
  O'Brien
  Adams
  de Jager
  Novák
  Rikl
  Haarhuis
  Plamer
RR
W–L
Set
W–L
Game
W–L
Standings
2   Todd Woodbridge
  Mark Woodforde
7–6(7–3), 6–4 6–2, 6–4
(w/ Novák / Rikl)
6–4, 6–2 3–0 6–0 37–22 1
4   Sébastien Lareau
  Alex O'Brien
6–7(3–7), 4–6 6–2, 7–6(7–5)
(w/ Adams / de Jager)
7–6(7–1), 6–2 2–1 4–2 36–29 2
5
9
  David Adams
  John-Laffnie de Jager
  Jiří Novák
  David Rikl
2–6, 4–6
(w/ Novák / Rikl)
2–6, 6–7(5–7)
(w/ Adams / de Jager)
4–6, 5–7
(w/ Adams / de Jager)
0–2
0–1
0–4
0–2
17–26
6–12
4
5
7   Paul Haarhuis
  Jared Palmer
4–6, 2–6 6–7(1–7), 2–6 6–4, 7–5
(w/ Adams / de Jager)
1–2 2–4 27–34 3

Standings are determined by: 1. number of wins; 2. number of matches; 3. in two-players-ties, head-to-head records; 4. in three-players-ties, percentage of sets won, or of games won; 5. steering-committee decision.

References

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  1. ^ "1999 ATP Tour World Championships – Doubles results". Association of Tennis Professionals (ATP).