1998 Chevrolet Cup – Doubles

Hendrik Jan Davids and Andrew Kratzmann were the defending champions, but did not participate this year.

Doubles
1998 Chevrolet Cup
Final
ChampionsArgentina Mariano Hood
Argentina Sebastián Prieto
Runners-upItaly Massimo Bertolini
United States Devin Bowen
Score7–6, 6–7, 7–6
Events
Singles Doubles
← 1997 · Chile Open · 2000 →

Mariano Hood and Sebastián Prieto won the title, defeating Massimo Bertolini and Devin Bowen 7–6, 6–7, 7–6 in the final.

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   D Orsanic
  D Roditi
6 7  
    M Carlsson
  F Meligeni
1 5   1   D Orsanic
  D Roditi
4 4  
    P Albano
  J Balcells
6 6 3     L Bale
  D Sapsford
6 6  
    L Bale
  D Sapsford
7 4 6     L Bale
  D Sapsford
6 6 4
3   M Hood
  S Prieto
6 6   3   M Hood
  S Prieto
4 7 6
    A Berasategui
  J Burillo
3 2   3   M Hood
  S Prieto
3 6 6
    G Kuerten
  R Schlachter
3 6 2     L Arnold
  M Puerta
6 0 3
    L Arnold
  M Puerta
6 4 6 3   M Hood
  S Prieto
7 6 7
    M Bertolin
  D Bowen
6 6       M Bertolin
  D Bowen
6 7 6
    G Köves
  A Sá
4 3       M Bertolin
  D Bowen
w/o    
    L Lobo
  M Ríos
6 6 6     L Lobo
  M Ríos
     
4   B Coupe
  P Rosner
2 7 1     M Bertolin
  D Bowen
7 6  
    D del Río
  M Rodríguez
6 7   WC   F Mantilla
  N Massú
6 3  
Q   Francisco Cabello
  E Medica
3 6       D del Río
  M Rodríguez
4 6 6
WC   F Mantilla
  N Massú
6 1 7 WC   F Mantilla
  N Massú
6 3 7
2   J Alonso
  N Lapentti
3 6 6

References

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