1998 Gold Flake Open – Doubles

Mahesh Bhupathi and Leander Paes were the defending champions. They successfully defended their title, defeating Olivier Delaître and Max Mirnyi in the final 6–7, 6–3, 6–2.

Doubles
1998 Gold Flake Open
Final
ChampionsIndia Mahesh Bhupathi
India Leander Paes
Runners-upFrance Olivier Delaître
Belarus Max Mirnyi
Score6–7, 6–3, 6–2
Events
Singles Doubles
← 1997 · Gold Flake Open · 1999 →

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   T Woodbridge
  M Woodforde
6 6  
    D DiLucia
  P Tramacchi
2 2   1   T Woodbridge
  M Woodforde
6 1  
WC   L Burgsmüller
  R Schüttler
6 1 1     A Clément
  J Golmard
7 6  
    A Clément
  J Golmard
4 6 6     A Clément
  J Golmard
3 2  
4   O Delaître
  M Mirnyi
6 6   4   O Delaître
  M Mirnyi
6 6  
WC   H Mankad
  G Natekar
1 2   4   O Delaître
  M Mirnyi
6 3 6
    M Ardinghi
  V Santopadre
6 6       M Ardinghi
  V Santopadre
3 6 2
    A Richardson
  M Wakefield
2 1   4   O Delaître
  M Mirnyi
7 3 2
WC   S Kirtane
  V Uppal
2 4   2   M Bhupathi
  L Paes
6 6 6
    B Cowan
  F Veglio
6 6       B Cowan
  F Veglio
2 6 7
Q   D Nainkin
  W Whitehouse
7 6   Q   D Nainkin
  W Whitehouse
6 4 6
3   J Salzenstein
  J Stark
6 4       B Cowan
  F Veglio
6 1 6
    P Luxa
  E Ran
6 6   2   M Bhupathi
  L Paes
2 6 7
    M Hilpert
  J Thomas
0 2       P Luxa
  E Ran
6 2 3
    S Groen
  A Pavel
3 6 5 2   M Bhupathi
  L Paes
3 6 6
2   M Bhupathi
  L Paes
6 3 7
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