1993 Comcast U.S. Indoor – Doubles

Todd Woodbridge and Mark Woodforde were the defending champions, but lost in the first round this year.

Doubles
1993 Comcast U.S. Indoor
Final
ChampionsUnited States Jim Grabb
United States Richey Reneberg
Runners-upSouth Africa Marcos Ondruska
United States Brad Pearce
Score6–7, 6–3, 6–0
Events
Singles Doubles
← 1992 · Comcast U.S. Indoor · 1994 →

Jim Grabb and Richey Reneberg won the title, defeating Marcos Ondruska and Brad Pearce 6–7, 6–3, 6–0 in the final.[1]

Seeds

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Draw

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Draw

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First round Quarterfinals Semifinals Final
1   J Grabb
  R Reneberg
6 6  
    B Garnett
  M Keil
4 4   1   J Grabb
  R Reneberg
6 6  
    J Pugh
  G Van Emburgh
6 3 2 WC   P Sampras
  J Tarango
4 2  
WC   P Sampras
  J Tarango
4 6 6 1   J Grabb
  R Reneberg
6 6  
3   P McEnroe
  J Palmer
2 6 6 3   P McEnroe
  J Palmer
3 1  
    N Broad
  S Kruger
6 1 1 3   P McEnroe
  J Palmer
6 6  
    K Kinnear
  S Salumaa
6 7       K Kinnear
  S Salumaa
1 4  
    M Briggs
  T Kronemann
4 6   1   J Grabb
  R Reneberg
6 6 6
    S Cannon
  S Melville
4 3       M Ondruska
  B Pearce
7 3 0
    G Michibata
  D Pate
6 6       G Michibata
  D Pate
2 3  
Q   C Allgårdh
  C Limberger
1 6   4   J Eltingh
  P Haarhuis
6 6  
4   J Eltingh
  P Haarhuis
6 7   4   J Eltingh
  P Haarhuis
5 4  
WC   B Gilbert
  E Sánchez
6 2 3     M Ondruska
  B Pearce
7 6  
    K Flach
  D Randall
4 6 6     K Flach
  D Randall
6 7 5
    M Ondruska
  B Pearce
6 7       M Ondruska
  B Pearce
7 6 7
2   T Woodbridge
  M Woodforde
3 6  

References

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  1. ^ John Barrett, ed. (1994). International Tennis Federation World of Tennis 1994. London: CollinsWillow. p. 122. ISBN 9780002184564.
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