1950 Iowa gubernatorial election

The 1950 Iowa gubernatorial election was held on November 7, 1950. Incumbent Republican William S. Beardsley defeated Democratic nominee Lester S. Gillette with 59.10% of the vote.

1950 Iowa gubernatorial election

← 1948 November 7, 1950 1952 →
 
Nominee William S. Beardsley Lester S. Gillette
Party Republican Democratic
Popular vote 506,642 347,176
Percentage 59.10% 40.50%

County results

Beardsley:      50-60%      60-70%      70-80%

Gillette:      50–60%

Governor before election

William S. Beardsley
Republican

Elected Governor

William S. Beardsley
Republican

Primary elections

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Primary elections were held on June 5, 1950.[1]

Democratic primary

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Candidates

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Results

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Democratic primary results[1]
Party Candidate Votes %
Democratic Lester S. Gillette 70,046
Democratic Myron J. Bennett 23,458
Total votes 93,504

Republican primary

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Candidates

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Results

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Republican primary results[1]
Party Candidate Votes %
Republican William S. Beardsley (incumbent) 238,686 100.00
Total votes 238,686 100.00

General election

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Candidates

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Major party candidates

  • William S. Beardsley, Republican
  • Lester S. Gillette, Democratic

Other candidates

  • W. Raymond Picken, Prohibition
  • Howard H. Tyler, Independent

Results

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1950 Iowa gubernatorial election[2]
Party Candidate Votes % ±%
Republican William S. Beardsley (incumbent) 506,642 59.10%
Democratic Lester S. Gillette 347,176 40.50%
Prohibition W. Raymond Picken 2,805 0.33%
Independent Howard H. Tyler 590 0.07%
Majority 159,466
Turnout 857,213
Republican hold Swing

References

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  1. ^ a b c "Summary of Official Canvass of Votes Cast in Iowa Primary Election" (PDF). Secretary of State of Iowa. 1950. Retrieved April 8, 2020.
  2. ^ "Summary of Official Canvass of Votes Cast in Iowa General Election" (PDF). Secretary of State of Iowa. 1950. Retrieved April 8, 2020.