1940 United States presidential election in Kentucky

The 1940 United States presidential election in Kentucky took place on November 5, 1940, as part of the 1940 United States presidential election. Kentucky voters chose eleven[2] representatives, or electors, to the Electoral College, who voted for president and vice president.

United States presidential election in Kentucky, 1940
Flag of Kentucky (1918-1963).png
← 1936 November 5, 1940[1] 1944 →

All 11 Kentucky votes to the Electoral College
  FDRoosevelt1938.png WendellWillkie.jpg
Nominee Franklin D. Roosevelt Wendell Willkie
Party Democratic Republican
Home state New York Indiana
Running mate Henry A. Wallace Charles L. McNary
Electoral vote 11 0
Popular vote 557,332 410,384
Percentage 57.45% 42.3%

President before election

Franklin D. Roosevelt
Democratic

Elected President

Franklin D. Roosevelt
Democratic

Kentucky was won by incumbent President Franklin D. Roosevelt (DNew York), running with Secretary Henry A. Wallace, with 57.45% of the popular vote, against Wendell Willkie (RIndiana), running with Minority Leader Charles L. McNary, with 42.30% of the popular vote.[3][4]

ResultsEdit

United States presidential election in Kentucky, 1940
Party Candidate Votes %
Democratic Franklin D. Roosevelt (inc.) 557,322 57.45%
Republican Wendell Willkie 410,384 42.30%
Write-in 2,457 0.25%
Total votes 970,163 100%

ReferencesEdit

  1. ^ "United States Presidential election of 1940 - Encyclopædia Britannica". Retrieved August 20, 2018.
  2. ^ "1940 Election for the Thirty-ninth Term (1941-45)". Retrieved August 20, 2018.
  3. ^ "1940 Presidential General Election Results - Kentucky". Retrieved August 20, 2018.
  4. ^ "The American Presidency Project - Election of 1940". Retrieved August 20, 2018.