1880 United States presidential election in Kansas(Redirected from United States presidential election in Kansas, 1880)
The 1880 United States presidential election in Kansas took place on November 2, 1880, as part of the 1880 United States presidential election. Voters chose five representatives, or electors to the Electoral College, who voted for president and vice president.
With 60.40% of the popular vote, Kansas would be Garfield's fifth strongest victory in terms of percentage in the popular vote after Vermont, Nebraska, Minnesota and Rhode Island. The state would also proved to be Weaver's fourth strongest state after Texas, Iowa, and Michigan.
|United States presidential election in Kansas, 1880|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Republican||James Abram Garfield of Ohio||Chester Alan Arthur of New York||121,549||60.40%||5||100.00%|
|Democratic||Winfield Scott Hancock of Pennsylvania||William Hayden English of Indiana||59,801||29.72%||0||0.00%|
|Greenback||James Baird Weaver of Iowa||Barzillai Jefferson Chambers of Texas||19,851||9.86%||0||0.00%|
|Anti-Masonic||John Wolcott Phelps of Vermont||Samuel Clarke Pomeroy of Kansas||25||0.01%||0||0.00%|
|Prohibition||Neal Dow of Maine||Henry Adams Thompson of Ohio||10||<0.01%||0||0.00%|
- "1880 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1880 Presidential General Election Results - Kansas".
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