1996 United States presidential election in Hawaii
The 1996 United States presidential election in Hawaii took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College, who voted for president and vice president.
Hawaii was won by President Bill Clinton (D) over Senator Bob Dole (R-KS), with Clinton winning 56.93% to 31.64% by a margin of 25.29%. Billionaire businessman Ross Perot (Reform Party of the United States of America-TX) finished in third, with 7.6% of the popular vote.
|1996 United States presidential election in Hawaii|
|Party||Candidate||Running mate||Votes||Percentage||Electoral votes|
|Democratic||Bill Clinton (incumbent)||Al Gore||205,012||56.93%||4|
|Republican||Bob Dole||Jack Kemp||113,943||31.64%||0|
|Reform||Ross Perot||Patrick Choate||27,358||7.60%||0|
|Green||Ralph Nader||Winona LaDuke||10,386||2.88%||0|
|Libertarian||Harry Browne||Jo Jorgensen||2,493||0.69%||0|
|Natural Law||Dr. John Hagelin||Dr. V. Tompkins||570||0.16%||0|
|U.S. Taxpayers' Party||Howard Phillips||Herbert Titus||358||0.10%||0|
- Leip, David. "Dave Leip's Atlas of U.S. Presidential Elections". uselectionatlas.org. Retrieved 2018-06-14.