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Summary
| Description |
English: Regular expression over the alphabet { 0, 1, S, E } whose complement expression has a length of about 232. "e" denotes the empty string. The example has been constructed from Thm.4.1, p.332 of: Wouter Gelade and Frank Neven (2008) "Succinctness of the Complement and Intersection of Regular Expressions" in Proc. 25th Ann. Symp. on the Theoretical Aspects of Computer Science (STACS), pp. 325–336 |
| Date | |
| Source | Own work |
| Author | Jochen Burghardt |
| Ascii source |
|---|
(e+(0+1+S+E)(e+(0+1+S+E)(e+(0+1+S+E)(e+(0+1+S+E)(e+(0+1+S+E)))))) + (e+(0+1)(e+(0+1)(e+(0+1)(e+(0+1))))) (S+E) (0+1+S+E)* + (0+1)(0+1)(0+1)(0+1)(0+1) (0+1+E) (0+1+S+E)* + (0+1+S+E)* S ( (e+(0+1+S+E)(e+(0+1+S+E)(e+(0+1+S+E)(e+(0+1+S+E))))) (S+E) + (0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E) (0+1+S) ) (0+1+S+E)* + (0+1+S+E)* E ( (e+(0+1+S+E)(e+(0+1+S+E)(e+(0+1+S+E)(e+(0+1+S+E))))) (S+E) + (0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E) (0+1+E) ) (0+1+S+E)* + (0+1+S+E)* (0+1+S) + ( (0+1)* + (0+1+S+E)* E (0+1)* ) 0 (0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E) 1 (0+1+S+E)* + ( (0+1)* + (0+1+S+E)* E (0+1)* ) 1 (0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E)(0+1+S+E) 0 (0+1+S+E)* |
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 11:11, 10 February 2021 | | 1,842 × 323 (4 KB) | Jochen Burghardt | Uploaded own work with UploadWizard |
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