English: Consider a couple of particles, each with a 2-dimensional state space (identified on the picture with the plane), and observables A, B and C, whose eigenvectors are as on the picture.
A couple prepared in the state psi has the following property. If the same observables are measured on both particles, by the construction the results would be the same. But measuring different observables one gets 0 on both particles with probability 1/8 (as well as for both observation providing 1). Thus the sum of the probabilities to get the same value measuring different observables (for 3 pairs of different observables) is 6/8.
On the other hand that sum should be at least 1, assuming that the results of all measurments are predetermined and, as it is in this case, same for both particles. Indeed, at least two out of three observables should be equal, so any predetermination contributes at least 1 to the sum.
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