2013 Sacramento Challenger – Doubles

Tennys Sandgren and Rhyne Williams were the defending champions, but they lost in the first round.

Doubles
2013 Sacramento Challenger
Final
ChampionsAustralia John-Patrick Smith
Australia Matt Reid
Runners-upUnited States Jarmere Jenkins
United States Donald Young
Score7–6(7–1), 4–6, [14–12]
Events
Singles Doubles
← 2012 · Sacramento Challenger · 2014 →

John-Patrick Smith and Matt Reid won the title, defeating Jarmere Jenkins and Donald Young in the final, 7–6(7–1), 4–6, [14–12].

Seeds edit

  1.   Samuel Groth /   Chris Guccione (first round)
  2.   John-Patrick Smith /   Matt Reid (champions)
  3.   Tennys Sandgren /   Rhyne Williams (first round)
  4.   Alex Kuznetsov /   Peter Polansky (first round, withdrew)

Draw edit

Key edit

Draw edit

First round Quarterfinals Semifinals Final
1   S Groth
  C Guccione
657 [6]
  C Ball
  D Molchanov
77 5 [10]     C Ball
  D Molchanov
2 77 [10]
    S Johnson
  T Smyczek
6677 [10]   S Johnson
  T Smyczek
6 65[3]
  M Arévalo
  D Cox
78 64[8]     C Ball
  D Molchanov
634
3   T Sandgren
  R Williams
3 2 WC   J Jenkins
  D Young
77 6
WC   J Jenkins
  D Young
6 6 WC   J Jenkins
  D Young
6 6
Q   N Meister
  D Nguyen
  P Gojowczyk
  D Zivkovic
3 2
  P Gojowczyk
  D Zivkovic
w/o WC   J Jenkins
  D Young
616 12
  A Krajicek
  D Kudla
6 6 2   M Reid
  J-P Smith
77 3 14
WC   Dennis Nevolo
  D Novikov
1 4     A Krajicek
  D Kudla
7 2 [6]
WC   R Kendrick
  Brian Martinez
w/o WC   R Kendrick
  B Martinez
5 6 [10]
4   A Kuznetsov
  P Polansky
WC   R Kendrick
  B Martinez
665
  R Ram
  B Reynolds
2   M Reid
  J-P Smith
78 7
  D Evans
  N Kyrgios
w/o     D Evans
  N Kyrgios
  B Klahn
  J McGee
4 2 2   M Reid
  J-P Smith
w/o
2   M Reid
  J-P Smith
6 6

References edit