Open main menu

1996 United States presidential election in Nevada

The 1996 United States presidential election in Nevada took place on November 5, 1996, as part of the 1996 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president.

United States presidential election in Nevada, 1996

← 1992 November 5, 1996 2000 →
  Bill Clinton.jpg Bob Dole, PCCWW photo portrait.JPG RossPerotColor.jpg
Nominee Bill Clinton Bob Dole Ross Perot
Party Democratic Republican Reform
Home state Arkansas Kansas Texas
Running mate Al Gore Jack Kemp Pat Choate
Electoral vote 4 0 0
Popular vote 203,974 199,244 43,986
Percentage 43.93% 42.91% 9.47%

Nevada Presidential Election Results by County, 1996.svg
County Results

President before election

Bill Clinton

Elected President

Bill Clinton

A swing state, Nevada was narrowly won by incumbent Democratic President Bill Clinton. Clinton took a 43.93% plurality of the popular vote over Republican challenger Bob Dole, who took 42.91%, a victory margin of 1.02%. Reform Party candidate Ross Perot finished in third, with 9.47% of the popular vote.[1]

As of the 2016 presidential election, this is the last presidential election in which the Democratic candidate won Nevada without carrying Washoe County, and the last time Mineral County voted Democratic. It is also the only time since 1960 that Nevada did not vote for the same candidate as Colorado.


United States presidential election in Nevada, 1996
Party Candidate Votes Percentage Electoral votes
Democratic Bill Clinton (incumbent) 203,974 43.93% 4
Republican Bob Dole 199,244 42.91% 0
Reform Ross Perot 43,986 9.47% 0
N/A None of these Candidates 5,608 1.21% 0
Green Ralph Nader 4,730 1.02% 0
Libertarian Harry Browne 4,460 0.96% 0
Ind. American Howard Phillips 1,732 0.37% 0
Natural Law John Hagelin 545 0.12% 0
Totals 464,279 100.00% 4


  1. ^ "1996 Presidential General Election Results". U.S. Election Atlas. Retrieved 30 January 2013.