The 1989 555 Asian Open was a professional ranking snooker tournament that took place in August 1989 in Bangkok, Thailand.[1]
Tournament information | |
---|---|
Dates | 17–27 August 1989 |
Venue | Channel 12 Studios |
City | Bangkok |
Country | Thailand |
Organisation | WPBSA |
Format | Ranking event |
Winner's share | £40,000 |
Final | |
Champion | Stephen Hendry (SCO) |
Runner-up | James Wattana (THA) |
Score | 9–6 |
1990 → |
Stephen Hendry won the tournament by defeating James Wattana 9–6 in the final.[2]
Main draw
editReferences
edit- ^ "Asian Open, Asian Classic, Hong Kong Open". Chris Turner's Snooker Archive. Archived from the original on 16 February 2012. Retrieved 2 March 2018.
- ^ "Asian Open". Snooker Scene. Archived from the original on 24 January 2013. Retrieved 2 March 2018.
- ^ Hayton, Eric. Cuesport Book of Professional Snooker. pp. 158–159.