1968 Wimbledon Championships – Boys' singles

John Alexander defeated Jacques Thamin in the final, 6–1, 6–2 to win the boys' singles tennis title at the 1968 Wimbledon Championships.[1]

Boys' singles
1968 Wimbledon Championships
ChampionAustralia John Alexander
Runner-upFrance Jacques Thamin
Final score6–1, 6–2
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1967 · Wimbledon Championships · 1969 →

DrawEdit

KeyEdit

FinalsEdit

Semifinals Final
          
  Jacques Thamin 6 7
  Stephen Warboys 4 5
  Jacques Thamin 1 2
  John Alexander 6 6
  John Alexander 5 6 6
  Adriano Panatta 7 1 3

Top halfEdit

First round Second round Quarterfinals Semifinals
  Jacques Thamin 6 6
  James McArdle 4 2
  J Thamin 3 6 6
  J Hordijk 6 3 3
  R Goldman 0 0
  Jan Hordijk 6 6   J Hordijk 6 6
  Witold Meres 1 4   J Thamin 6 7
  E Wagner-Smitt 6 6   S Warboys 4 5
  Erick Ulleberg 4 3   E Wagner-Smitt 6 3
  Holger Osinski 4 9 4   J Andrew 8 6
  Jorge Andrew 6 7 6   J Andrew 3 1
  Ian Baudinet w/o   S Warboys 6 6
  Stephen Warboys   S Warboys 6 6
  HM Lufti 6 1 6   HM Lufti 4 4
  Michel Burgener 2 6 3

Bottom halfEdit

First round Second round Quarterfinals Semifinals
  Robert Van Malder 10 7
  N Đuranović 8 5   R Van Malder 3 1
  Eustace Kigongo 2 4   J Hřebec 6 6
  Jiří Hřebec 6 6   J Hřebec 3 2
  Antonio Muñoz 1 1   J Alexander 6 6
  John Alexander 6 6   J Alexander 6 6
  János Benyik 6 6   J Benyik 3 1
  Peter Feigl 3 4   J Alexander 5 6 6
  P Crovetto 0 1   A Panatta 7 1 3
  Fernando Gentil 6 6   F Gentil 4 7
  Adriano Panatta 6 9
  A Panatta 6 4 6
  T Larsen 2 6 1
  Evan Phillips 0 0
  Terje Larsen 6 6

ReferencesEdit

  1. ^ "Boys' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.

External linksEdit