1968 United States presidential election in Iowa
The 1968 United States presidential election in Iowa took place on November 5, 1968, as part of the 1968 United States presidential election. Iowa voters chose nine representatives, or electors, to the Electoral College, who voted for president and vice president.
Iowa was won by the Republican candidate, former Vice President Richard Nixon, with 53.01% of the popular vote, against the Democratic candidate, former Senator and incumbent Vice President Hubert Humphrey, with 40.82% of the popular vote. American Independent Party candidate George Wallace performed decently, finishing with 5.69% of the popular vote.
|American Independent||George Wallace||66,422||5.69%|
|Socialist Workers||Fred Halstead||3,377||0.29%|
- "United States Presidential election of 1968 - Encyclopædia Britannica". Retrieved May 25, 2017.
- "1968 Election for the Forty-Sixth Term (1969-73)". Retrieved May 25, 2017.
- "1968 Presidential General Election Results - Iowa". Retrieved May 25, 2017.
- "The American Presidency Project - Election of 1968". Retrieved May 25, 2017.
- Although he was born in California and he served as a U.S. Senator from California, in 1968 Richard Nixon’s official state of residence was New York, because he moved there to practice law after his defeat in the 1962 California gubernatorial election. During his first term as president, Nixon re-established his residency in California. Consequently, most reliable reference books list Nixon's home state as New York in the 1968 election and his home state as California in the 1972 (and 1960) election.
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