1966 United States Senate election in Rhode Island

The 1966 United States Senate election in Rhode Island took place on November 8, 1966. Incumbent Democratic U.S. Senator Claiborne Pell successfully sought re-election, defeating Republican Ruth M. Briggs with 67.66% of the vote.

1966 United States Senate election in Rhode Island

← 1960 November 8, 1966 1972 →
  Sen Claiborne Pell.jpg No image.svg
Nominee Claiborne Pell Ruth M. Briggs
Party Democratic Republican
Popular vote 219,331 104,838
Percentage 67.66% 32.34%

1966 United States Senate election in Rhode Island results map by county.svg
County results
Pell:      50–60%      60–70%      70–80%

U.S. senator before election

Claiborne Pell
Democratic

Elected U.S. Senator

Claiborne Pell
Democratic

Primary electionsEdit

Primary elections were held on September 13, 1966.

Democratic primaryEdit

CandidatesEdit

ResultsEdit

Democratic primary results[1][2]
Party Candidate Votes %
Democratic Claiborne Pell unopposed

Republican primaryEdit

CandidatesEdit

ResultsEdit

Republican primary results[1][2]
Party Candidate Votes %
Republican Ruth M. Briggs 15,451 82.13%
Republican Charles H. Eden 3,363 17.87%
Total votes 18,814 100.00%

General electionEdit

ResultsEdit

General election results [4][5][6][7]
Party Candidate Votes %
Democratic Claiborne Pell (Incumbent) 219,331 67.66
Republican Ruth M. Briggs 104,838 32.34
Majority 114,493 35.32
Turnout 324,169
Democratic hold

ReferencesEdit

  1. ^ a b Congressional Quarterly 1998, p. 150.
  2. ^ a b America Votes 7, p. 372.
  3. ^ "Rhode Island". Des Moines Tribune. Des Moines, Iowa. 14 September 1966. p. 3. Retrieved 3 July 2021.
  4. ^ Clerk of the U.S. House of Representatives (1967). "Statistics of the Presidential and Congressional Election of November 8, 1966" (PDF). U.S. Government Printing Office.
  5. ^ "RI US Senate, 1966". OurCampaigns. Retrieved 3 July 2021.
  6. ^ Congressional Quarterly 1998, p. 96.
  7. ^ America Votes 7, p. 352.

BibliographyEdit

External linksEdit