1939 U.S. National Championships – Women's Singles

First-seeded Alice Marble defeated second-seeded Helen Jacobs 6–0, 8–10, 6–4 in the final to win the Women's Singles tennis title at the 1939 U.S. National Championships. The tournament was played on outdoor grass courts and held from September 7, through September 17, 1939 at the West Side Tennis Club in Forest Hills, Queens, New York.[1][2]

Women's Singles
1939 U.S. National Championships
ChampionUnited States Alice Marble[1]
Runner-upUnited States Helen Jacobs
Final score6–0, 8–10, 6–4
Details
Draw64
Seeds8
Events
Singles men women
Doubles men women
← 1938 · U.S. National Championships · 1940 →

The draw consisted of 64 players of which eight were seeded.

SeedsEdit

The eight seeded U.S. players are listed below. Alice Marble is the champion; others show in brackets the round in which they were eliminated.

  1.   Alice Marble (Champion)
  2.   Helen Jacobs (Finalist)
  3.   Sarah Fabyan (Quarterfinalist)
  4.   Dorothy Bundy (Quarterfinalist)
  5.   Gracyn Wheeler (First round)
  6.   Helen Bernard (Third round)
  7.   Dorothy Workman (Third round)
  8.   Virginia Wolfenden (Semifinalist)

DrawEdit

Final eightEdit

Quarterfinals Semifinals Finals
               
2   Helen Jacobs 2 6 6
  Valerie Scott 6 2 3
2   Helen Jacobs 7 6
  Kay Stammers 5 0 4
3   Sarah Fabyan 6 3 3
  Kay Stammers 1 6 6
2   Helen Jacobs 0 10 4
1   Alice Marble 6 8 6
1   Alice Marble 6 6 6
  Mary Hardwick 3 8 2
1   Alice Marble 6 6
8   Virginia Wolfenden 0 1
4   Dorothy Bundy 6 1 2
8   Virginia Wolfenden 2 6 6

ReferencesEdit

  1. ^ a b Collins, Bud (2016). The Bud Collins History of Tennis (3rd ed.). New York: New Chapter Press. p. 498. ISBN 978-1-937559-38-0.
  2. ^ "Rigs defeats Van Horn". The Advocate (Tasmania). Tasmania, Australia. 19 September 1939. p. 3 – via National Library of Australia.