1892 United States presidential election in Massachusetts
The 1892 United States presidential election in Massachusetts took place on November 8, 1892, as part of the 1892 United States presidential election. Voters chose 15 representatives, or electors to the Electoral College, who voted for president and vice president.
|Turnout||74.6 2.9 pp|
Massachusetts voted for the Republican nominee, incumbent President Benjamin Harrison, over the Democratic nominee, former President Grover Cleveland, who was running for a second, non-consecutive term. Harrison won the state by a narrow margin of 6.65%.
|1892 United States presidential election in Massachusetts|
|Party||Candidate||Running mate||Popular vote||Electoral vote|
|Republican||Benjamin Harrison of Indiana||Whitelaw Reid of New York||202,814||51.87%||15||100.00%|
|Democratic||Grover Cleveland of New York||Adlai Ewing Stevenson I of Illinois||176,813||45.22%||0||0.00%|
|Prohibition||John Bidwell of California||James Cranfill of Texas||7,539||1.93%||0||0.00%|
|People's||James Baird Weaver of Iowa||James Gaven Field of Virginia||3,210||0.82%||0||0.00%|
|Socialist Labor||Simon Wing of Massachusetts||Charles Matchett of New York||649||0.16%||0||0.00%|
- Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- "1892 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
- "1892 Presidential General Election Results - Massachusetts". U.S. Election Atlas. Retrieved 23 December 2013.
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