1872 United States presidential election in Iowa

The 1872 United States presidential election in Iowa took place on November 5, 1872. All contemporary 37 states were part of the 1872 United States presidential election. The state voters chose 11 electors to the Electoral College, which selected the president and vice president.

1872 United States presidential election in Iowa

← 1868 November 5, 1872 1876 →
  UlyssesGrant.jpg Horace Greeley restored (cropped).jpg
Nominee Ulysses S. Grant Horace Greeley
Party Republican Liberal Republican
Home state Illinois New York
Running mate Henry Wilson Benjamin G. Brown
Electoral vote 11 0
Popular vote 131,566 81,636[a]
Percentage 60.81% 37.73%[a]

Iowa Presidential Election Results 1872.svg
County Results

President before election

Ulysses S. Grant
Republican

Elected President

Ulysses S. Grant
Republican

Iowa was won by the Republican nominees, incumbent President Ulysses S. Grant of Illinois and his running mate Senator Henry Wilson of Massachusetts. Grant and Wilson defeated the Liberal Republican and Democratic nominees, former Congressman Horace Greeley of New York and his running mate former Senator and Governor Benjamin Gratz Brown of Missouri.

Grant won the state by a margin of 23.08%.

ResultsEdit

1872 United States presidential election in Iowa[1]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Republican Ulysses S. Grant of Illinois Henry Wilson of Massachusetts 131,566 60.81% 11 100.00%
Liberal Republican Horace Greeley of New York Benjamin Gratz Brown of Missouri 81,636[a] 37.73%[a] 0 0.00%
Bourbon Democrat Charles O'Conor John Quincy Adams II 2,221 1.03% 0 0.00%
Write-ins N/A N/A 942 0.44% 0 0.00%
Total 216,365 100.00% 11 100.00%

See alsoEdit

NotesEdit

  1. ^ a b c d Greeley won 71,189 votes (32.9%) as the Liberal nominee, and 10,447 votes (4.83%) as the Liberal Republican Nominee.

ReferencesEdit

  1. ^ "1872 Presidential General Election Results - Iowa".