1868 United States presidential election in Louisiana

The 1868 United States presidential election in Louisiana took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

1868 United States presidential election in Louisiana

← 1864 November 3, 1868 1872 →
  Hon. Horatio Seymour, N.Y - NARA - 528568 (cropped).jpg Ulysses S Grant by Brady c1870-restored (3x4 crop).jpg
Nominee Horatio Seymour Ulysses S. Grant
Party Democratic Republican
Home state New York Illinois
Running mate Francis Preston Blair, Jr. Schuyler Colfax
Electoral vote 7 0
Popular vote 80,225 33,263
Percentage 70.69% 29.31%

President before election

Andrew Johnson

Elected President

Ulysses S. Grant

Amid widespread violence and threats meant to prevent freedmen from voting, Louisiana voted for the Democratic nominee, former Governor of New York Horatio Seymour, over the Republican nominee, General Ulysses S. Grant. Seymour won the state by a margin of 41.38%.

With 70.69% of the popular vote, Louisiana would be Seymour's second strongest victory in terms of percentage in the popular vote after Kentucky.[1]


1868 United States presidential election in Louisiana[2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Horatio Seymour of New York Francis Preston Blair, Jr. of Missouri 80,225 70.69% 7 100.00%
Republican Ulysses S. Grant of Illinois Schuyler Colfax of Indiana 33,263 29.31% 0 0.00%
Total 113,488 100.00% 7 100.00%

See alsoEdit


  1. ^ "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved 2018-03-05.
  2. ^ "1868 Presidential General Election Results - Louisiana".