1868 New Jersey gubernatorial election

The 1868 New Jersey gubernatorial election was held on November 3, 1868. Democratic nominee Theodore Fitz Randolph defeated Republican nominee John Insley Blair with 51.42% of the vote.

1868 New Jersey gubernatorial election

← 1865 November 3, 1868 1871 →
  Theodore Fitz Randolph (cropped).jpg John I. Blair (cropped).jpg
Nominee Theodore Fitz Randolph John Insley Blair
Party Democratic Republican
Popular vote 83,955 79,333
Percentage 51.42% 48.58%

Governor before election

Marcus Lawrence Ward
Republican

Elected Governor

Theodore Fitz Randolph
Democratic

General electionEdit

CandidatesEdit

ResultsEdit

New Jersey gubernatorial election, 1868[1]
Party Candidate Votes % ±%
Democratic Theodore Fitz Randolph 83,955 51.42%   2.49
Republican John Insley Blair 79,333 48.58%   2.49
Total votes 163,288
Democratic gain from Republican Swing

ReferencesEdit

  1. ^ Kalb, Deborah (24 December 2015). Guide to U.S. Elections. ISBN 9781483380353. Retrieved 2016-01-25.