1859 Wisconsin gubernatorial election

The 1859 Wisconsin gubernatorial election was held on November 8, 1859. Republican Party incumbent Governor Alexander Randall won re-election with 53% of the vote, defeating Democratic candidate Harrison Carroll Hobart.[1]

1859 Wisconsin gubernatorial election
← 1857 November 8, 1859 1861 →
  AWRandall.jpg HarrisonCHobart.jpg
Nominee Alexander W. Randall Harrison Carroll Hobart
Party Republican Democratic
Popular vote 59,999 52,539
Percentage 53.21% 46.60%

1859 Wisconsin gubernatorial election results map by county.svg
County results
Randall:      50–60%      60–70%      70–80%
Hobart:      50–60%      60–70%      70–80%

Governor before election

Alexander W. Randall

Elected Governor

Alexander W. Randall

Democratic PartyEdit

Harrison Carroll Hobart was a member of the Wisconsin State Assembly at the time of the election, representing Calumet County. He had previously served as Speaker of the Assembly in the 1849 session, and was state senator for the 1st district in the 1st Wisconsin Legislature.

Republican PartyEdit

Alexander W. Randall was the incumbent Governor, having been elected in the 1857 election. He had previously served as a Wisconsin Circuit Court Judge in Milwaukee, and served one term in the Wisconsin State Assembly in 1855. Earlier, in 1846, Randall had been a delegate to the first Wisconsin constitutional convention and had successfully advocated for including a provision by which African American suffrage could be legalized via referendum.


Wisconsin Gubernatorial Election, 1859
Party Candidate Votes % ±%
General Election, November 8, 1859
Republican Alexander Randall (incumbent) 59,999 53.21% +3.58%
Democratic Harrison Carroll Hobart 52,539 46.60% -2.53%
Scattering 83 0.07%
Total votes 112,755 100.0% +25.20%
Republican hold


  1. ^ Joint Committee on Legislative Organization, Wisconsin Legislature (2015). Wisconsin Blue Book 2015-2016. Madison, Wisconsin: Wisconsin Department of Administration. pp. 699–701. ISBN 978-0-9752820-7-6.