1852 United States presidential election in Missouri

The 1852 United States presidential election in Missouri took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose nine representatives, or electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in Missouri

← 1848 November 2, 1852 1856 →
  Mathew Brady - Franklin Pierce (cropped).jpg Winfield Scott by Fredricks, 1862 (cropped).jpg
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote 9 0
Popular vote 38,817 29,984
Percentage 56.42% 43.58%

President before election

Millard Fillmore
Whig

Elected President

Franklin Pierce
Democratic

Missouri voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Missouri by a margin of 12.84%.

ResultsEdit

1852 United States presidential election in Missouri[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 38,817 56.42% 9 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 29,984 43.58% 0 0.00%
Total 68,801 100.00% 9 100.00%

See alsoEdit

ReferencesEdit

  1. ^ "1852 Presidential General Election Results - Missouri". U.S. Election Atlas. Retrieved 2 December 2017.
  2. ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.