1852 United States presidential election in Maryland

The 1852 United States presidential election in Maryland took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose eight representatives, or electors to the Electoral College, who voted for President and Vice President.

1852 United States presidential election in Maryland

← 1848 November 2, 1852 1856 →
  Mathew Brady - Franklin Pierce (cropped).jpg Winfield Scott by Fredricks, 1862 (cropped).jpg
Nominee Franklin Pierce Winfield Scott
Party Democratic Whig
Home state New Hampshire New Jersey
Running mate William R. King William A. Graham
Electoral vote 8 0
Popular vote 40,022 35,077
Percentage 53.28% 46.69%

President before election

Millard Fillmore

Elected President

Franklin Pierce

Maryland voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. Pierce won Maryland by a margin of 6.59%. This was the first presidential election in which Maryland voted Democratic.


1852 United States presidential election in Maryland[1][2]
Party Candidate Running mate Popular vote Electoral vote
Count % Count %
Democratic Franklin Pierce of New Hampshire William R. King of Alabama 40,022 53.28% 8 100.00%
Whig Winfield Scott of New Jersey William A. Graham of North Carolina 35,077 46.69% 0 0.00%
Free Soil John P. Hale of New Hampshire George W. Julian of Indiana 21 0.03% 0 0.00%
Total 75,120 100.00% 8 100.00%

See alsoEdit


  1. ^ "1852 Presidential General Election Results - Maryland". U.S. Election Atlas. Retrieved 2 December 2017.
  2. ^ "1852 Presidential Election". The American Presidency Project. University of California Santa Barbara. Retrieved 2 December 2017.