1845 Virginia gubernatorial election

The 1845 Virginia gubernatorial election was held on 10 December 1845 in order to elect the Governor of Virginia. Democratic nominee and former U.S. House representative William Smith defeated John Brockenbrough and 15 other candidates.

1845 Virginia gubernatorial election

← 1842 10 December 1845 1848 →
 
Nominee William Smith John Brockenbrough Valentine W. Southall
Party Democratic
Legislature vote 94 (58.75%) 40 (25.00%) 11 (6.88%)

Governor before election

James McDowell
Democratic

Elected Governor

William Smith
Democratic

General election

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On 10 December 1845, the Virginian General Assembly began voting for governor. William Smith, who had previously been selected by a caucus to be Democratic nominee,[1] was nominated alongside John Brockenbrough and 14 other candidates. Smith won a majority of the votes and was sworn in as governor on 1 January 1846.[2][3]

Results

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Senate ballot[2]
Party Candidate Votes %
Democratic William Smith 20 66.67
John Brockenbrough 6 20.00
Four others one each 4 13.33
Valid votes 30 100
Total 30 100
House of Delegates ballot[3]
Party Candidate Votes %
Democratic William Smith 74 56.92
John Brockenbrough 34 26.15
Valentine W. Southall 11 8.46
William Cabell Rives 2 1.54
Andrew Stevenson 2 1.54
Seven others one each 7 5.38
Valid votes 130 100
Total 130 100
Joint total[2][3]
Party Candidate Votes %
Democratic William Smith 94 58.75
John Brockenbrough 40 25.00
Valentine W. Southall 11 6.88
James Lyons 2 1.25
William Cabell Rives 2 1.25
Andrew Stevenson 2 1.25
9 others one each 9 5.63
Valid votes 160 100
Total 160 100

References

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  1. ^ Harper, Kenton (December 18, 1845). "Virginia Legislature". Staunton Spectator And General Advertiser. p. 2.
  2. ^ a b c Barber, J. H. (December 20, 1845). "State Elections". Newport Mercury. p. 3.
  3. ^ a b c Virginia General Assembly (1845). Journal of the House of Delegates of the Commonwealth of Virginia. Superintendent Public Printing.