1788–89 United States presidential election in Delaware

Main article: 1788–89 United States presidential election

The 1788–89 United States presidential election in Delaware took place on January 7, 1789 as part of the 1788–1789 United States presidential election to elect the first President. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

1788–1789 United States presidential election in Delaware

January 7, 1789

Nominee George Washington John Jay Party Independent Independent Home state Virginia New York Electoral vote 3 3 Popular vote 685 0 Percentage 100.00% 0.00%

President before election Office established Elected President George Washington Independent

George Mitchell, John Baning, and Gunning Bedford Jr. served as electors. George Washington and John Jay both received three electoral votes.

Results

United States presidential election in Delaware, 1789
Party		Candidate	Votes	Percentage	Electoral votes
	Independent	George Washington	685	100.00%	3
Totals			685	100.00%	3

See also

• United States presidential elections in Delaware

Works cited

• Jensen, Merrill; Becker, Robert, eds. (1976). The First Federal Elections 1788-1790: Congress, South Carolina, Pennsylvania, Massachusetts, New Hampshire. Vol. 1. University of Wisconsin Press. ISBN 0299066908.