United States presidential election in Montana, 1896

      United States presidential election in Montana, 1896
      Montana
      1892 ←
      November 3, 1896 (1896-11-03)
      → 1900

        WilliamJBryan1902.png William McKinley by Courtney Art Studio, 1896.jpg
      Nominee William Jennings Bryan William McKinley
      Party Democratic Republican
      Home state Nebraska Ohio
      Running mate Arthur Sewall Garret Hobart
      Electoral vote 3 0
      Popular vote 42,628 10,509
      Percentage 79.93% 19.71%

      MT1896president.png

      County results

      President before election

      Grover Cleveland
      Democratic

      Elected President

      William McKinley
      Republican

      The 1896 United States presidential election in Montana took place on November 3, 1896 throughout 45 states. Voters chose 3 representatives, or electors to the Electoral College, who voted for President and Vice President.

      Montana overwhelmingly voted for the Democratic nominee, former U.S. Representative from Nebraska William Jennings Bryan over the Republican nominee, former governor of Ohio William McKinley. Bryan won Montana by a landslide margin of 60.22%.

      Bryan's support for many Populist goals resulted in him being nominated by both the Democratic Party and the People's Party (Populists), though with different running mates. One electoral vote from Montana was cast for the Populist Bryan-Watson ticket with Thomas E. Watson as Vice-President and two votes were cast for the Bryan-Sewall ticket.

      Results

      United States presidential [1]
      Party Candidate Votes Percentage Electoral votes
      Democratic William Jennings Bryan 42,628 79.93% 3
      Republican William McKinley 10,509 19.71% 0
      Prohibition Joshua Levering 193 0.36% 0
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      Last modified on 24 March 2013, at 13:04