1998 United States Senate election in Iowa
(Redirected from United States Senate election in Iowa, 1998)
The 1998 United States Senate election in Iowa was held November 3, 1998. Incumbent Republican United States Senator Chuck Grassley sought re-election to a fourth term in the United States Senate, running against former State Representative David Osterberg, who won the Democratic nomination unopposed. Grassley had not faced a competitive election since 1980; this year proved no different, and Grassley defeated Osterberg in a landslide.
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County results Grassley: 50-60% 60-70% 70-80% 80-90% >90% | |||||||||||||||||
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Democratic primary edit
Candidates edit
- David Osterberg, former State Representative
Results edit
Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic | David Osterberg | 86,064 | 99.45% | |
Democratic | Write-ins | 476 | 0.55% | |
Total votes | 86,540 | 100.00% |
Republican primary edit
Candidates edit
- Chuck Grassley, incumbent United States Senator
Results edit
Party | Candidate | Votes | % | |
---|---|---|---|---|
Republican | Chuck Grassley (Incumbent) | 149,943 | 99.72% | |
Republican | Write-ins | 419 | 0.28% | |
Total votes | 150,362 | 100.00% |
General election edit
Results edit
Party | Candidate | Votes | % | ±% | |
---|---|---|---|---|---|
Republican | Chuck Grassley (Incumbent) | 648,480 | 68.41% | -1.20% | |
Democratic | David Osterberg | 289,049 | 30.49% | +3.29% | |
Natural Law | Susan Marcus | 7,561 | 0.80% | -0.47% | |
Socialist Workers | Margaret Trowe | 2,542 | 0.27% | +0.16% | |
Write-ins | 275 | 0.03% | |||
Majority | 359,431 | 37.92% | -4.50% | ||
Turnout | 947,907 | ||||
Republican hold | Swing |
See also edit
References edit
- ^ a b "Results" (PDF). sos.iowa.gov. 1998. Retrieved October 15, 2019.
- ^ "Election info" (PDF). clerk.house.gov. 1998. Retrieved October 15, 2019.