1946 Massachusetts gubernatorial election

(Redirected from Francis D. Harrigan)

The 1946 Massachusetts gubernatorial election was held on November 5, 1946. Republican Robert F. Bradford defeated Democratic incumbent Maurice J. Tobin, Socialist Labor candidate Horace Hillis, and Prohibition candidate Guy S. Williams.

1946 Massachusetts gubernatorial election

← 1944 November 5, 1946 1948 →
 
Nominee Robert F. Bradford Maurice J. Tobin
Party Republican Democratic
Popular vote 911,152 762,743
Percentage 54.12% 45.30%

Bradford:      40–50%      50–60%      60–70%      70–80%      80–90%      >90%
Tobin:      40–50%      50–60%      60–70%      70–80%

Governor before election

Maurice J. Tobin
Democratic

Elected Governor

Robert F. Bradford
Republican

Democratic primary

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Governor Tobin defeated Francis D. Harrigan, a senior partner with the law firm of Caulfield, Harrigan and Murray, associate editor of the Association of Trial Lawyers of America's Law Journal, and a World War I veteran, for the Democratic nomination.[1][2]

Democratic gubernatorial primary, 1946[1]
Party Candidate Votes % ±%
Democratic Maurice J. Tobin (incumbent) 194,529 75.70%
Democratic Francis D. Harrigan 62,418 24.30%

Republican primary

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Lieutenant Governor Robert F. Bradford won the Republican gubernatorial nomination unopposed.[3]

General election

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Results

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Massachusetts gubernatorial election, 1946[4]
Party Candidate Votes % ±%
Republican Robert F. Bradford 911,152 54.12%
Democratic Maurice J. Tobin (incumbent) 762,743 45.30%
Socialist Labor Horace Hillis 7,140 0.42%
Prohibition Guy S. Williams 2,408 0.16%

See also

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References

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  1. ^ a b Election Statistics; The Commonwealth of Massachusetts 1946.
  2. ^ "Francis D. Harrigan, once ran for governor". The Boston Daily Globe. November 17, 1969.
  3. ^ Election Statistics; The Commonwealth of Massachusetts 1946.
  4. ^ Election Statistics; The Commonwealth of Massachusetts 1946.