File:Sallows triangle theorem.svg

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Description Visual proof of Lee Sallows's triangle theorem by CMG Lee. 1. Lines from midpoints of edges of length a, b and c (circles) to the opposite vertex split the triangle into 6 regions. 2. Each region is rotated 90 degrees outwards about its hinge, yielding 3 congruent triangles with sides equal and perpendicular to the line segments between the original triangle's vertices and its centroid (2x, 2y and 2z). 3. The process can be repeated on each smaller triangle. 4. Each resulting triangle has sides a/3, b/3 and c/3, similar to but 1/9 the area of the original.
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Author Cmglee

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Date/TimeThumbnailDimensionsUserComment
current21:47, 4 March 2024Thumbnail for version as of 21:47, 4 March 2024512 × 512 (10 KB)Cmglee{{Information |Description=Visual proof of Lee Sallows's triangle theorem by CMG Lee. 1. Lines from midpoints of edges of length ''a'', ''b'' and ''c'' (circles) to the opposite vertex split the triangle into 6 regions. 2. Each region is rotated 90 degrees outwards about its hinge, yielding 3 congruent triangles with sides equal and perpendicular to the line segments between the original triangle's vertices and its centroid (2''x'', 2''y'' and 2''z''). 3. The process can be repeated on each s...
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